#include <map>
using namespace std;

template<typename T, typename T0>
class MyMap : public std::map<T,T0>
{
public:
    void foo();

};

template<typename T, typename T0>
void MyMap<T,T0>::foo()
{

    for(iterator it(begin()); it!=end(); ++it)   //<-- compile time error
        it->bla();

    //klappt auch nicht:
    //for(MyMap<T,T0>::iterator it(begin()); it!=end(); ++it)
    //    it->bla();
}

Es gibt Probleme mit dem statement: iterator it(begin())

Any help?

thx in advance

So funktionierts, siehe dazu: http://www.slac.stanford.edu/BFROOT/www/Computing/Programming/GCCWarnings.html

this is because the C++ standard rule is that every identifier that involves a template is interpreted as a value unless it is explicitly qualified as a typename. Thus, when you write;

vector<T>::const_iterator i;

const_iterator may be interpreted as a static member of the class vector<T>. To make it clear that it is the type that declares the value i, one needs to write;

typename vector<T>::const_iterator i;

Da waere ich auch nicht von alleine drauf gekommen..
Vielen Dank!

Na, das is ja mal ein Ding

this is because the C++ standard rule is that every identifier that involves a template is interpreted as a value unless it is explicitly qualified as a typename. Thus, when you write;

vector<T>::const_iterator i;

const_iterator may be interpreted as a static member of the class vector<T>. To make it clear that it is the type that declares the value i, one needs to write;

typename vector<T>::const_iterator i;

Da waere ich auch nicht von alleine drauf gekommen..
Vielen Dank!

Wenn du dich jetzt eventuell noch fragst, warum? Dann ist dieser Link imho ebenfalls hilfreich: http://www.gotw.ca/gotw/035.htm.

Gruß Caipi