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Hallo,
ich brauch ne Idee wie ich folgendes zeigen kann:
für 0<x<n+2 gilt
x^(n+1)/(n+1)! <= Summe(k=0 bis n) (x^k)/k! <= ((x^(n+1))/(n+1)!) * ((1)/(1-x/(n+2)))
<= (kleiner gleich) ^ (hoch)