hello world programm inline asm

hey i read this and wanted to make some simple try and stuck on first step...

just simple hello world i cant get adress of the char so i tried by db it doesnt work here my try:
so i cant use $msg here really really shitti declaring char msg[] = "hello world"; and try $msg doesnt work too

maybe someone can help
i also assembled the programm and tried to vget adress of it by reading asm code but seg fault in here...

int main ()
{
asm ("msg db 'Hello world',$0x0A\n\t"
"movl $4 ,%eax\n\t"
"movl $1 ,%ebx\n\t"
"movl $msg,%ecx\n\t"
"movl $len ,%edx\n\t"
"int $0x80 \n\t"
"movl $1,%eax \n\t "
"int $0x80"
);

}

nachtfeuer

http://www.c-plusplus.net/forum/viewtopic-var-t-is-197875.html

bzw. der Link darin:
http://www.ibiblio.org/gferg/ldp/GCC-Inline-Assembly-HOWTO.html

#include <stdio.h>

int main( void )
{
char test[] = "hello world";

__asm__("movl $4, %%eax; movl $1, %%ebx\n"
"movl %0, %%ecx\n"
"movl $13, %%edx\n"
"int $0x80"
:: "m"(*test)

);
}

This is still not working...

Hallo ich hab das mal geduggert und wenn ich %% benutze werden zb am anfang keine 4 zugewiesen sondern -14 ...

mit %%:
eax 0xfffffff2 -14

mit %

eax 0x4 4

.

abc.w

@someoneee: Und so funktioniert es bei mir:
tmp.c:

int main(int argc, char* argv[])
{
    char test[] = "hello world\n";

    argc = argc;
    argv = argv;

    __asm__ (
            "movl $4, %%eax\n\t"
            "movl $1, %%ebx\n\t"
            "leal %0, %%ecx\n\t"
            "movl $12, %%edx\n\t"
            "int $0x80"
            :: "m"(*test));

    return 0;
}

gcc tmp.c -o tmp

Tipp: Schau dir die Assembler-Ausgabe des Compilers an!

gcc -S tmp.c

cat tmp.s

hi abc.w

danke nochmal nachträglich genau das habe ich gesucht