what does (int &int) mean ?

[euklid]

Dear friends, I do not know what (int & int ) mean?
I thought it will be either true or false according as the value 0 or something else. But here, this is not the case.
Would you please write the answer and make it understand?

// program : prog
#include<stdio.h>
#include<stdlib.h>
int main (int argc, char** argv){
        int x = atoi(argv[1]);
        int y = atoi(argv[2]);
        printf("your integer: %i! \n",(x&y));

return 0;}

e.g : ./prog 2 17 =>2 , ./prog 2 18 => 2 , ./prog 4 18 => 0, ./prog 31 32 => 0
How is the result calculated here?
Thank you so much in Advance !
Euklid

[cooky451]

& is the binary and, google for binary operators. The logical and (the one that's either true or false) is &&.

[euklid]

ok ! Thank you so much for the answer! I understood now !!
Hier is the answer:
http://en.wikipedia.org/wiki/Bitwise_operation#AND
with best wishes